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0=4g^2+3g+11
We move all terms to the left:
0-(4g^2+3g+11)=0
We add all the numbers together, and all the variables
-(4g^2+3g+11)=0
We get rid of parentheses
-4g^2-3g-11=0
a = -4; b = -3; c = -11;
Δ = b2-4ac
Δ = -32-4·(-4)·(-11)
Δ = -167
Delta is less than zero, so there is no solution for the equation
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